$$\text{Moment} = \text{Force} \times \text{Perpendicular distance from the pivot}$$
$$\boldsymbol{M} = \boldsymbol{F} \times \boldsymbol{v}$$
$$\sum M_{CW} = \sum M_{ACW}$$
$$F_{1}d_{1}=F_{2}d_{2}$$

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Turning Effect

$$\vec{M} = \frac{\Delta \vec{L}}{\Delta t}, \text{where } \vec{L}=m\vec{v}\times\vec{r} = m\vec{\omega}$$

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20. C
21. $60\times {0.5} = 20\times {1.5}$ equal
22. $W \times 3 = 120 \times 1 + 160 \times 3$ $W = 200$
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  1. $M=\vec{F} \times \vec{d}$
  2. $\sum M_{CW} = \sum M_{ACW}$
  3. $M=Fd$
  4. $520\times 0.5=260\ N\cdot m$
  5. $260 = 6.5w$ $w = 40$
  6. apply force at the farthest point